prvi cir pola rada | Page 17

Uc= - UL –UR = - L di –Ri = -AL(p1ep1t –p2ep2t) – RA(ep1t –ep2t)
Dt
Uc(0)=Uo= -AL(p1 – p2) =>A= - Uo. = Uo.
(6)
L(p1 – p2)√R2 – 4L/C
I(t) = - E . e-(R/2L)t sin(ωt) коначан израз за струју

(7)

UL(t)= L di(t) => UL(t)= -E e-(R/2L)t(cos(ωt) – R . sin(ωt))
dt
2ωL
Uc(t)= - Ri(t) –UL(t) => Uc(t)=ER.e-(R /2L)t sin(ωt) + Ee-(R/2L)tcos(ωt)
2ωL