N mbg =
N b, m = k m, uncr f ′ m h ef
1.5
N b, m =( 17)( 1, 500 psi)( 5 in.) 1. 5 N b, m = 7, 361 lbs
184 in. 2 1. 0 0. 787 1. 0 7, 361 lbs
225 in. 2 N mbg = 4, 737 lbs
A Nm
Bond failure— Nominal strength
N mag = A Na A Nao ψ ec, Na ψ ed, Na N ba, m
c Na = 10d a τ uncr, m 1, 100 psi
1, 074 psi c Na = 10( 0.5 in.)
1, 100 psi c Na = 4.94 in. ψ ed, Na = 0.7 + 0.3 c a, min c Na 2. 187 in. ψ ed, Na = 0.7 + 0.3
4.94 in. ψ ed, Na = 0.833
N ba, m = τ uncr, m πd a h ef N ba, m = 1, 074 psi π 0.5in.)( 5 in.)
N mag = A Na A Nao
N mag =
Controlling design strength
Nua ϕ steel N sa
=
N ba, m = 8, 435 lbs
ψ ec, Na ψ ed, Na N ba, m
127 in. 2
1. 0 0. 833 8, 435 lbs 98 in. 2 N mag = 9, 106 lbs
250 lbs 0.75 8, 230 lbs = 4. 05 %
N ua ϕ masonry N mbg
=
N ua ϕ bond N mag
=
500 lbs 0.65 4, 737 lbs
= 16. 24 %
500 lbs 0.65 9, 106 lbs = 8. 45 %
Shear failure modes
Steel failure— Nominal strength
V sa = 0.60 A se, V f uta V sa =( 0.60)( 0.1419 in. 2)( 58, 000 psi) V sa = 4, 938 lbs
Masonry breakout failure— Nominal strength
V mbg = A Vm
A Vmo ψ ec, V, m ψ ed, V, m ψ m, V ψ h, V, m ψ parallel, V, m V b, m
A Na = c Na + 8 in. + c Na c Na + 2. 187 in. A Na = 2 4.94 in. + 8 in. 4.94 in. + 2. 187 in. A Na = 127 in. 2
A Nao =( 2c Na) 2 A Nao =( 2( 4.94in.)) 2 A Nao = 98 in. 2 ψ ec, Na = 1.0( No Eccentricity Present)
11