Mi primera revista PROGRMACION FINAL PORTAFOLIO | Page 18

1
2
3
1
0
0
A −1 = [
1
3
3|
0
1
0]
1
2
4
0
0
1
1
2
3
1
0
0
A −1 = [
0
1
0|
−1
1
0]
0
0
1
−1
0
1
1
0
3
3
−2
0
A −1 = [
0
1
0|
−1
1
0]
0
0
1
−1
0
1
1
0
0
6
−2
−3
A −1 = [
0
1
0|
−1
1
0
]
0
0
1
−1
0
1
RESPUESTA
6
−2
−3
A = [
−1
1
0
]
−1
0
1
3∗3
COMPROBACIÓN A ∗ A −1 = I
1
2
3
A = [
1
3
3]
1
2
4
3∗3
6
−2
−3
A = [
−1
1
0
]
−1
0
1
3∗3
( 1 )( 6 ) + ( 2 )( −1 ) + ( 3 )( −1 )
( 1 )( −2 ) + ( 2 )( 1 ) + ( 3 )( 0 )
( 1 )( −3 ) + ( 2 )( 0 ) + ( 3 )( 1 )
A ∗ A −1 =
[( 1 )( 6 ) + ( 3 )( −1 ) + ( 3 )( −1 )
( 1 )( −2 ) + ( 3 )( 1 ) + ( 3 )( 0 )
( 1 )( −3 ) + ( 3 )( 0 ) + ( 3 )( 1
)]
( 1 )( 6 ) + ( 2 )( −1 ) + ( 4 )( −1 )
( 1 )( −2 ) + ( 2 )( 1 ) + ( 4 )( 0 )
( 1 )( −3 ) + ( 2 )( 0 ) + ( 4 )( 1 )
6 + ( −2 ) + ( −3 )
−2 + 2 + 0
−3 + 0 + 3
A ∗ A −1 = [
6 + ( −3 ) + ( −3 )
−2 + 3 + 0
−3 + 0 +
3]
6 + ( −2 ) + ( −4 )
−2 + 2 + 0
−3 + 0 + 4
RESPUESTA
1
0
0
A ∗ A −1 = [
0
1
0]
0
0
1
3∗3
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