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Table 36. Nominal Steel Strength in Tension( N sa) N sa = ESR value ESR-4868 Table 11
N sa = 13,110 lb / anchor
Nominal Concrete Breakout Strength in Tension( N cbg)
N cbg =
A ACI 318-19 Eq.( 17.6.2.1b) Nc ψ A ec, N ψ ed, N ψ c, N ψ cp, N N b Nc0 h ef = 8.0 in 1.5h ef = 12.0 in 3.0h ef = 24.0 in
A Nc =( c x- + s x + c x +)( c y- + s y12 + s y23 + s x34 + c y +) =( 4.0 + 6.0 + 8.0)( 12.0 + 8.0 + 8.0 + 8.0 + 12.0)
ψ ec, N =
= 864 in 2 c x- = 4 in
s x = 6 in
ACI 318-19 Fig. R17.6.2.1 b)
c x + = 8 in c y- = ∞ = 1.5h ef
s y12 = 8 in s y23 = 8 in s y34 = 8 in A Nc0 = 9( h ef) 2 = 9( 8 in) 2 = 576 in 2 ACI 318-19 Eq.( 17.6.2.1.4)
1 1 + e ′ N
1.5h e f
= 1.0 no tension eccentricity ACI 318-19 Eq.( 17.6.2.3.1) e’ N = 0 in ψ ed, N = 0.7 + 0.3 c a, min 1.5h e f
= 0.7 +( 0.3)(( 4.0 in / 12.0 in) = 0.80
ACI 318-19 Eq.( 17.6.2.4.1b) c a, min = c x- = 4.0 in 1.5h ef = 12.0 in
ψ c, N = 1.0 cracked or uncracked concrete Reference ACI 318-19 17.6.2.5.1
ψ cp, N = MAX c a, min | 1. 5h e f
= 1.0 cracked concrete Reference ACI 318-19 17.6.2.6.1. c ac c ac c y + = ∞ in = 1.5h ef
N b = k c, xxxx λ a f ′ c h e f
1.5
normal weight concrete: λ = 1.0 → λ a = 1.0 N b =( 17)( 1.0)( 4000 psi) 0. 5( 8.0 in) 1. 5 = 24,328 lb
N cbg =
A Nc A Nc0 ψ ec, N ψ ed, N ψ c, N ψ cp, N N b
N cbg =( 864 in 2 / 576 in 2)( 1.0)( 0.80)( 1.0)( 1.0)( 24,328 lb) = 29,194 lb
ACI 318-19 Eq.( 17.6.2.2.1) ACI 318-19 Table 17.2.4.1 k c, cr = 17 Reference ESR-4868 Table 12 f ' c = 4000 psi h ef = 8.0 in
A Nc = 864 in 2 A Nc0 = 576 in 2 ψ ec, N = 1.0 ψ ed, N = 0.80 ψ c, N = 1.0 ψ cp, N = 1.0 N b = 24,328 lb
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