Design guide for considering concrete breakout in shear using ACI 318 anchoring-to-concrete provisions October 2025 | Page 130

PROFIS ENGINEERING
Plate
Concrete f’ c = 4000 psi
h concrete = 24 in
10” x 2’- 4” x 5 / 8” length( N) = 10.0 in width( B) = 28.0 in thickness( t pl) = 0.625 in default rigid assumption no stand-off type: normal weight lightweight – λ = N / A concrete condition: cracked hole condition: dry Temperature: 72 0 F Temp Range A( max. long term = 110 0 F, max. short term = 130 0 F) Supplementary Reinforcement tension: not present shear: not present edge reinf.: N / A
Table 34. Resultant Tension / Shear Loads and Individual Tension / Shear Loads
Anchor
Tension Load( lb / anchor)
Sustained Tension Load
( lb / anchor)
Shear Load( lb / anchor)
Shear Load x-direction( lb / anchor)
Shear Load y-direction( lb / anchor) 1 1000 750 625 0-625 2 1000 750 625 0-625 3 1000 750 625 0-625 4 1000 750 625 0-625 5 1000 750 625 0-625 6 1000 750 625 0-625 7 1000 750 625 0-625 8 1000 750 625 0-625
Tension eccentricity e c1, N( x direction) = 0.00 in
Resultant Tension Load( N ua) = 8000 lb
e c2, N( y direction) = 0.00 in
Shear eccentricity e cV = 0.00 in
Resultant Shear Load( V ua, y) =-5000 lb 1000 = highest loaded anchor in tension 625 = highest loaded anchor in shear 750 = highest( sustained) loaded anchor in tension
Table 35. Geometry Checks
h ef = 8.0 in ESR-4868 Table 12
c x- = 4.0 in c x + = 8.0 in ESR-4868 Table 12 c y- = ∞ c y + = ∞ h ef, min = 3.125 in h ef, max = 12.5 in
c min = 2.0 in
8.0 in > 3.125 in OK 8.0 in < 12.5 in OK c min, actual = c x- 4.0 in > 2.0 in OK
s x = 6.0 in
s ynn = 8.0 in
ESR-4868 Table 12
s min = 3.125 in
h concrete = 24.0 in
ESR-4868 Table 12
h min = h ef + 2d hole
d hole = 0.75 in
ESR-4868 Figure 1 [ 2 ]
= 9.5 in
s min, actual = s x 6.0 in > 3.125 in OK
24.0 in > 9.5 in OK
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