Apps. and Interpretation for IBDP Maths Ebook 1 | Page 129

Solution
(a) y � 6
A1 N1
(b) (i) (5, 5) A1 N1
[1]
(ii) The equation of L :
y�5 � �3( x� 5)
(M1) for substitution
y� �3x� 20
A1 N2
.
(iii) 6 � �3x
� 20
(M1) for substitution
3x � 14
14
x �
3
�14 �
Thus, the required coordinates are � ,6 �
� 3 � A1 N2 [5]
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