OCZ Introduces Onyx2 range of SSDs
S
AN JOSE, CA—September
27, 2010—OCZ Technology
Group, Inc. (Nasdaq:OCZ),
a leading provider of highperformance solid-state drives
(SSDs) and memory modules for
computing devices and systems,
has unveiled the OCZ Onyx 2
Series, a 2.5 inch SSD with
superior affordability designed
for mainstream desktops and
mobile systems. Offering a faster
and more durable alternative
to traditional hard drives in a
cost-efficient solution, the Onyx
2 delivers excellent performance
with lower price per gigabyte
than that of other comparable
drives on the market.
“While we are constantly
looking to push the envelope in
solid state drive performance,
we are also dedicated to
making the technology more
affordable to consumers,” said
Ryan Petersen, CEO of the
OCZ Technology Group. “The
new Onyx 2 Series SSDs give
customers the very best of
both worlds when it comes to
performance and value, and they
are an ideal solution for mobile
and desktop users that want to
take advantage of all the benefits
that SSDs offer over traditional
rotational based drives.”
OCZ continues to expand its
consumer SSD lineup with the
goals of not only delivering
cutting-edge performance,
but also o ?????????MM?()??????????????????????????)???????????????????????????)???????????????????????)?????????????????????)M????????????=?????)??????????5??????????5??)??????????????????????????)????%=AL???????????????????)?????????????????????)????????????????????????????????51??????????????)Q???=?????MM??????????)???????????????????????????)??????????????????????????)????????????????????????)??????????????????????????)???????????????????????)?????????????????????QI%4()??????????????????]??????(????????)=
h?=?????MM?????????)???????????????????????????)???????????????????)???????????????????????)???????????????????????)????????????????????)????????????????????)=???????????????????????)??????????????????????MM)?????????????????????????)????????????????????????)???????????????=L?????????)????????????????????????????)=?????M???????????????(??????????????????)?????????????????()-???????
??????????????A??5?????M?????)P()????e???????????????)??????????????????)????????????????????????)??????????A=P??????????)???????????????????????)????????????????????)??????????????]???????)??????????????????????????????((?Q???=??
??????=?????????()???????????????????????)?????????????????????????)A=P?????q???????t??????????)??????????????????)????????????????????Q??)???????????????9???M???)???????????????????????????)????????????????()%???????????????????????)????????????????????????????)?????????????????????????????)??e?????????A=P????????????????)??????????????????
AU?)???????????????????)????????????????)?????????????((