The META Scholar Volume 2 | Page 18

TMS Didactic Muse Page 18 Imaging Ultrasound Cont. Amplitude of the ultrasound beam decaying exponentially in time and the echo is amplified in reverse. is dependent on the difference of acoustic impedance of the interfaces that produce the echo. Let’s go back to the water container. When the waves collide with the first mesh, part of it returns to the cork, and the other go through the first mesh. The part of the waves that go through cannot be of the same amplitude as the ones that collided with the first mesh, so the amplitude is smaller and it happens each time the waves collide with a mesh. As it is colliding, it keeps on losing amplitude and the reflections are smaller. It also happens to the ultrasound beam. As long as the beam is traveling it is suffering attenuation and the amplitude is decaying exponentially as it goes deeper in the body. It also can be said, that it is decaying exponentially with the time because more elapsed time means that the ultrasound beam travels deeper. The decaying is because of the reflections, refractions and frictions with the molecules of the tissues. (fig. 20) has the same structure as fig. 10, and also the same differences of acoustic impedances, but in (fig. 20) is taken into account the attenuation of the ultrasound beam. The interfaces, I1 and I3 have the same differences of acoustic impedances, so both have to produce echoes of the same amplitude, but on account of the attenuation it is not possible and the echo produced at I3 is smaller and on screen appears as wrong information of the echo. It appears on screen as points with different brightness because of the difference of amplitude between them coming from equal reflection coefficient interfaces, and the two points ought to be of equals brightness. The problem cannot be solved by supplying bigger power to the beam in the transmission because attenuation is always present and the farther interface will always receive the ultrasound beam with more attenuation than the interfaces near the probe. The solution is in the reception process. As the echoes from I1 and I3 must have the same amplitude, and is impossible to obtain that equality at the interfaces, it is necessary to amplify more the echo form I3 than the one from I1 so the difference of amplitude applied to the echo from I3