SteMath Solutions For Problems | страница 12

PROBLEM 1
ANSWER OF THE PROBLEM:
COMPETITOR A � HEADS COMPETITOR B � TAILS
IN THE 3 rd SHOT � 2 TAILS 1 HEADS CAME.
4 SHOTS WILL BE MADE � 2 4 =16 PROBABILITY
4!
� 4 TAILS 0 HEADS � B WINS �
4! = 1 , 1 ⁄
16
4!
� 3 TAILS 1 HEADS � B WINS � = 4 3! , 4 ⁄
16
� 2 TAILS 2 HEADS � B WINS � = 6 6
2!.2! , ⁄
16
� 1 TAILS 3 HEADS �A WINS � 4!
= 4 , 4 ⁄
3! 16
� 0 TAILS 4 HEADS � A WINS � 4!
= 1 , 1 ⁄
4! 16
B’S PROBABILITY OF WINING � 1
+ 4
+ 6 = 11
16 16 16 16
A’S PROBABILITY OF WINING � 4 + 1
= 5 16 16 16
∞ THE PRIZE SHOULD BE DIVIDED ACCORDING TO THE
PROBABLITIES.
4!
HASANCAN D. / ÖZLEM K.