Protection Engineering Basics and Schemes Protection Engineering | Page 233

V KP = 2 ∗ V R = 2 ∗ 41.7 V KP = 83.4volts

R stabilizing = R S =( V R

I R

) −( VA( I R) 2)

Relay setting at 1A( 20 % of 2500 = 500A); burden is 1VA

R S =( 41. 7 1) −( 1 1 2)

R S = 40.7ohms Relay setting at 2A( 40 % of 2500 = 1000A);

R S =( 41. 7 2) −( 1 2 2)

R S = 20.6ohms Relay setting at 5A( 100 % of 2500 = 2500A);

R S =( 41. 7 5) −( 1 5 2)

R S = 8.3ohms pg. 233