PROFIS ENGINEERING
CAS
3 s’ applique aux rangées 1 et 2: calculez V cbg de la rangée 1 en utilisant c a1, rangée 1.
V b = 7 l e d a
0.2 d a λ a f ′ c c a1
1.5
Consultez la zone ombragée en orange.
ACI 318-19 Eq.( 17.7.2.2.1a) l e = MIN h e f | 8d a
= 6,0 po h ef = 10 po d a = 0,75 po
Béton de poids normal: λ = 1,0 → λ a = 1,0 ACI 318-19 Tableau 17.2.4.1
V b = [( 7)( 6,0 po / 0,75 po) 0, 2( 0,75 po) 0, 5 ]( 1,0)( 5 000 psi) 0, 5( 6,0 po) 1, 5
= 9 549 lb V b = 9 λ a f ′ c c a1
1.5 f’ c = 5000 psi
ACI 318-19 Eq.( 17.7.2.2.1b)
c a1, rangée 1 = 6,0 po
8d a = 6,0 po CONTROLS
V b =( 9)( 1,0)( 5 000 psi) 0, 5( 6,0 po) 1, 5 = 9 353 lb vérifcation: conception V b = MIN { 9 549 lb; 9 353 lb }
V cbg =
A Vc A Vc0
= 9 353 lb
ψ ec, V ψ ed, V ψ c, V ψ h, V ψ parallel, V V b
V cbg, rangée 1 =( 405 po 2 / 162 po 2)( 1,0)( 1,0)( 1,2)( 1,0)( 1,0)( 9 353 lb)
= 28 059 lb
f’ c = 5000 psi |
c a1, rangée 1 = 6,0 po |
ACI 318-19 17.7.2.2 |
A Vc = 405 po 2 |
A Vc0 = 162 po 2 |
ψ ec, V = 1,0 |
ψ ed, V = 1,0 |
ψ c, V = 1,2 |
ψ h, V = 1,0 |
ψ parallèle, V = 1,0 |
V b = 9 353 lb |
[ en ] October 2025 98