PROFIS ENGINEERING
Tableau 8. Résistance nominale à l’ acier en tension( N sa) N sa = valeur ESR N sa = 26 780 lb / ancrage
ESR-3814 Tableau 6A
Résistance nominale à la rupture du béton en tension( N cbg)
N cbg =
A ACI 318-19 Eq.( 17.6.2.1b) Nc ψ A ec, N ψ ed, N ψ c, N ψ cp, N N b Nc0 h ef = 12,0 po 1,5h ef = 18,0 po 3,0h ef = 36,0 po
A Nc =( c x- + s x1 + s x2 + s x3 + c x +)( c y- + s y12 + s y23 + s x34 + c y +) =( 18,0 + 9,0 + 9,0 + 9,0 + 18,0)( 6,0 + 8,0 + 8,0 + 8,0 + 18,0) = 3 024 po 2
A Nc0 = 9( h ef) 2 c x- = ∞ po = 1,5 h ef
ACI 318-19 Fig. R17.6.2.1 b) c x + = ∞ po = 1,5 h ef c y- = 6 po
s x1 = 9 po s x2 = 9 po s x3 = 9 po s y12 = 8 po s y23 = 8 po s y34 = 8 po c y + = ∞ po = 1,5 h ef
= 9( 12 po) 2 ACI 318-19 Éq.( 17.6.2.1.4) ψ ec, N =
= 1 296 po 2 1 1 + e ′ N
1.5h e f
ACI 318-19 Éq.( 17.6.2.3.1) ψ ec, N = 1,0 pas d’ excentricité e’ N = 0 po 1,5h ef = 18 po ψ ed, N = 0.7 + 0.3 c a, min 1.5h e f
ACI 318-19 Eq.( 17.6.2.4.1b) ψ ed, N = 0,7 +( 0,3)(( 6,0 po / 18 po) = 0,8 c a, min = c y- = 6,0 po 1,5 h ef = 18,0 po
ψ c, N = 1,0 béton fissuré ou non fissuré Consultez ACI 318-19 17.6.2.5.1
ψ cp, N = MAX c a, min
| 1. 5h e f c ac c ac
ψ cp, N = 1,0 béton fissuré N b = k c, xxxx λ a f ′ c h e f
1.5
Béton de poids normal: λ = 1,0 → λ a = 1,0
N cbg =
N b =( 17)( 1,0)( 4 500 psi) 0, 5( 12,0 po) 1, 5
A Nc A Nc0
= 47 405 lb
ψ ec, N ψ ed, N ψ c, N ψ cp, N N b
N cbg =( 3 024 po 2 / 1 296 po 2)( 1,0)( 0,8)( 1,0)( 1,0)( 47 405 lb) = 88 489 lb
Consultez ACI 318-19 17.6.2.6.1.
ACI 318-19 Éq.( 17.6.2.2.1) ACI 318-19 Tableau 17.2.4.1 k c, cr = 17 Consultez la norme ESR-3814 tableau 7 f’ c = 4 500 psi h ef = 12 po
A Nc = 3 024 po 2 A Nc0 = 1 296 po 2 ψ ec, N = 1,0 ψ ed, N = 0,8 ψ c, N = 1,0 ψ cp, N = 1,0 N b = 47 405 lb
[ en ] October 2025 73