PROFIS ENGINEERING
N ag =
A Na A Na0 ψ ec, Na ψ ed, Na ψ cp, Na N ba ACI 318-19 Eq.( 17.6.5.1b)
c Na = 10d a τ uncr 1100
conception τ k, uncr =( ESR τ k, uncr)( f ' c / 2 500 psi) 0, 1 =( 2 220 psi)( 3 500 psi / 2 500 psi) 0, 1 = 2 296 psi c Na =( 10)( 0,75 po)( 2 296 psi / 1 100 psi) 0, 5 = 10,84 po
ACI 318-19 Eq.( 17.6.5.1.2b)
Consultez la norme ESR-4868 tableau 15 pour les valeurs τ k, uncr et() xx.
ESR τ k, uncr = 2 220 psi d a = 0,75 po() xx = 0,10 f’ c = 3 500 psi
A Na =( c x- + s x12 + s x23 + s x34 + c x +)( c y- + s y12 + s y23 + s x34 + c y +) =( 10,84 + 4,0 + 4,0 + 16,0 + 10,84)( 6,0 + 4,0 + 8,0 + 8,0 + 10,84) = 1 682,85 po 2 c x- = ∞ po = c Na
ACI 318-19 Fig. R17.6.5.1( b) c x + = ∞ po = c Na c y- = 6 po
s x 12 = 4 po s x23 = 4 po s x34 = 16 po s y12 = 4 po s y23 = 8 po s y34 = 8 po
A Na0 =( 2c Na) 2 =( 21,68 po) 2 = 470,02 po 2 ACI 318-19 Eq.( 17.6.5.1.2a)
ψ ec, Na =
1 1 + e ′ N c Na
ecc.( x direction):. ec1, N = 0,783 ecc.( y direction):. ec2, N = 0,916. Cec, N =(. ec1, N)(. ec2, N) =( 0,783)( 0,916) = 0,717 c Na = 10,84 po ACI 318-19 Éq.( 17.6.5.3.1)
2c Na = 21,68 po
c y + = ∞ po = c Na
x direction: e c1, N = 3,0 po c Na = 10,84 po y direction: e c2, N = 1,0 po ψ ed, Na = 0.7 + 0.3 c a, min c Na
= 0,7 +( 0,3)( 6,0 po / 10,84 po) = 0,866
Consultez ACI 318-19 Eq.( 17.6.5.4.1b)
c a, min = c y- = 6,0 po c Na = 10,84 po ψ cp, Na = MAX c a, min | c Na
= 1.0 béton fissuré Consultez ACI 318-19 Eq.( 17.6.5.5.1b) c ac c ac
N ba = λ a α N, seis τ xxxx πd a h e f
ACI 318-19 Éq.( 17.6.5.2.1)
Consultez la norme ESR-4868 tableau 15 pour les valeurs α N, seis. Béton de poids normal: λ = 1,0 → λ a = 1,0 ACI 318-19 Tableau 17.2.4.1
conception τ k, cr =( ESR τ k, cr)( f ' c / 2 500 psi) 0, 1 =( 1 260 psi)( 3 500 psi / 2 500 psi) 0, 1 = 1 303 psi
Consultez la norme ESR-4868 tableau 15 pour les valeurs τ k, cr et() xx.
ESR τ k, cr = 1 260 psi f ' c = 3 500 psi() xx = 0,1 N ba =( 1,0)( 1,0)( 1 303 psi)( π)( 0,75 po)( 14,0 po) = 42 982 lb d a = 0,75 po α N, seis = 1,0 h ef = 14,0 po
N ag =
A Na A Na0 ψ ec, Na ψ ed, Na ψ cp, Na N ba
Nag =( 1 682,85 / 470,02)( 0,717)( 0,866)( 1,0)( 42 982) = 95 554 lb
Tableau 26. Résistance nominale à l’ acier en cisaillement( V sa)
A Na = 1 682,85 dans 2 A Na0 = 470,02 dans 2 ψ ec, Na = 0,717 ψ ed, Na = 0,866 ψ cp, Na = 1,0 N ba = 42 982 lb
V sa = 11 640 lb / ancrage
Consultez la norme ESR-4868 tableau 11 pour les valeurs V sa. Consultez la norme ESR-4868 tableau 11 pour les valeurs α V, seis = S / O.
[ en ] October 2025 107