3.0 MODULAR SUPPORT SYSTEM 3.1.2 MT BEAM AND COLUMN LOAD TABLES
Modular Support Systems Technical Guide , Edition 1
Table 12 - Load and Deflection Factors for Beams |
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Span and Loading Condition |
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Load Factor |
Deflection Factor |
Simple Beam - Uniform Load 1.00 1.00
Simple Beam - Concentrated Load at Mid-span 0.50 0.80
Simple Beam - Two Equal Concentrated Loads at 1 / 4 Points
1.00 1.10
Beam Fixed at Both Ends - Uniform Load 1.50 0.30
Beam Fixed at Both Ends - Concentrated Load at Mid-span 1.00 0.40
Cantilever Beam - Uniform Load 0.25 2.40
Cantilever Beam - Concentrated Load at End 0.12 3.20
Continuous Beam - Two Equal Spans , Uniform Load on One Span
1.3 0.92
Continuous Beam - Two Equal Spans , Uniform Load on Both Spans
1.00 0.42
Continuous Beam - Two Equal Spans , Concentrated Load at Center of One Span
0.62 0.71
Continuous Beam - Two Equal Spans , Concentrated Load at Center of Both Spans
0.67 0.48
The allowable beam load tables in this technical guide are for single-span supported beams with uniform loading . Common arrangements of other load and support conditions are shown in the above table . Loads and deflections for these conditions can be determined by multiplying the load value from the tables by the given load and deflection factors . Additional reduction factors for unbraced beam lengths may apply per the tables on page 49 .
EXAMPLE 1 ) Determine the maximum allowable load and deflection for an MT-50 fully braced cantilever beam with a concentrated load at the unsupported end . SOLUTION : 1 . Allowable load and deflection for an MT-50 with a 48 " span from Table 19 on Page 35 is 1,000 lbs and 0.24 ".
2 . Multiply by factors from above table : Load = ( 1,000 lbs -1.97 x 4 ) x 0.12 = 119 lbs Deflection = 0.24 " x 3.20 = 0.77 "
EXAMPLE 2 ) Determine the maximum allowable load and deflection for a two-span MT-70 fully braced continuous beam that is uniformly loaded on one span . SOLUTION : 1 . Allowable load and deflection for an MT-70 with a 48 " span from Table 25 on Page 37 is 2,520 lbs and 0.28 ".
2 . Multiply by factors from above table : Load = ( 2,520 lbs -2.64 x 4 ) x 1.3 = 3,260 lbs Deflection = 0.28 " x 0.92 = 0.26 "
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