1. Anchor
Channel Systems
2. HAC
Portfolio
3. HAC
Applications
4. Design
Introduction
5. Base material
6. Loading
Acute and obtuse corners
9.6.5 — HAC (T) EDGE, HAC (T) EDGE LITE AND HAC S (T) EDGE
DESIGN: TOP AND BOTTOM OF SLAB OUTSIDE CORNER WITH
PAIR OF ANCHOR CHANNELS
Corner Rebar Top of Slab (EDGE C) 90°, Acute and obtuse corners
In order to install two EDGE front plates close to an edge some
modifications to the geometry of the product are needed.
Indeed, the rebar location of one EDGE Plate (EDGE C) needs
to be lower, in order to avoid clashing with the rebars of the
adjacnet corner channel. This is illustrated in Figure 9.6.5.1. Please refer section 9.2.10 for details on analyzing the obtuse
and acute angle corner with pair HAC (T) EDGE or HAC S (T)
EDGE anchor channel at the outside corner. Also refer 9.6.3
and 9.6.4 on details for analyzes and all the failure modes and
interaction that needed to be taken into consideration.
For this application, one element is a standard EDGE and the
second is the so-called Corner Rebar Top of Slab (EDGE C)
front plate.
Figure 9.6.5.1 — TOS or BOS HAC (T) EDGE C anchor channel — e R .
9. Special Anchor
Channel Design
10. Design
Software
11. Best
Practices
12. Instructions
for Use
13. Field Fixes
14. Design
Example
10. D
ESIGN
SOFTWARE
PROFIS Anchor Channel allows users to quickly and accurately model anchor channel system
applications. Through a simple, user-friendly interface, the verification of 20 anchor channel failure
modes and 5 interaction equations can be done in seconds.
PROFIS Anchor Channel allows users to design anchor channels with anchor reinforcement.
Moreover, the so called anchor channels with “rebars” (HAC CRFoS U and HAC EDGE) are available.
The software also allows users to design even the most complex applications such as seismic,
corners, and applications in lightweight concrete and thin slabs.
The EDGE C front plate is 20 mm higher and has the rebar 14 mm
deeper in order to cross those of the other EDGE element. The
thickness of the plate is increased to 6 mm instead of 5, in order to
resist the bending moment due to the larger lever arm. The other
geometrical dimensions, as well as the position and number of the
rebars remains the same as described in chapter 02.
8. Reinforcing
Bar Anchorage
The vertical distance of the rebar center point from the concrete
surface is for the EDGE C: e r = h ch + 3d/2 + 2 [mm]
Refer Figure 9.6.5.1 for the description. This e R will effect the
magnitude of tension force that the rebars will experience
as described below. Refer Figure 9.6.5.2 for the example of
determining the rebar forces
It will not be possible to select a EDGE C front plate as stand-
alone in Profis. A EDGE C will be automatically adopted when
the corner is activated on the second edge.
å A
'
r , i
li n = 4.93. Iy 0.05 . s 0.5
Figure 9.6.5.2 — Example for the calculation of rebar forces in accordance
with the triangular load distribution method for an anchor channel with four
rebars. The influence length is assumed as ℓin = 1.5s.
l in , r = (0.2 + 0.004 c a 1 ) l in £ l in in
s = anchor spacing , in
V b ua = factored tension load on channel bolt , lb
t = anchor plate thickness
e c = dist between concrete top
surface and anchor plate bottom surface
z = 0 .85. h '
d b
£ min(2. h ef , 2. c a 1 )
2
h = actual member depth
h ' = h - h ch -
h ch = height of anchor channel
h ef = embedment depth of the anchor
under consideration
c a 1 = edge dis tan ce of the anchor
under consideration
e s = e c +
310
k = 1
3 d
t
+ h ch + b + 0.07 87
2
2
for EDGE C , in
Please refer section 9.2.7 for details on analyzing the obtuse and acute angle corner with single anchor HAC EDGE channel at
the corner. Also refer 9.6.3 and 9.6.4 on details for analyzes and all the failure modes and interaction that needed to be taken into
consideration.
7. Anchor Channel
Design Code
A' 1 = 0.25 × s
1
=
l in
6
A' 2 = 1.25 × s
5
=
l in
6
A' 3 = 0.75 × s
1
=
l in
2
k =
1
2
=
A' 1 + A' 2 + A' 3 3
æ e
ö æ 1 ö
æ e
ö
æ 1 ö æ 2 ö
N ua r ,1 = ç ÷ . ç ÷ . V ua b . ç s + 1 ÷ = ç ÷ . V ua b . ç s + 1 ÷
è 6 ø è 3 ø
è z
ø è 9 ø
è z
ø
ö æ 5 ö b æ e s
ö
æ 5 ö æ 2 ö b æ e s
r
N ua ,2 = ç ÷ . ç ÷ . V ua . ç + 1 ÷ = ç ÷ . V ua . ç + 1 ÷
è 6 ø è 3 ø
è z
ø è 9 ø
è z
ø
æ e
ö æ 1 ö
æ e
ö
æ 1 ö æ 2 ö
N ua r ,3 = ç ÷ . ç ÷ . V ua b . ç s + 1 ÷ = ç ÷ . V ua b . ç s + 1 ÷
è 2 ø è 3 ø
è z
ø è 3 ø
è z
ø
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