Plumbing Africa November 2019 | Page 59

TECHNICAL 57 The physics of solar water geysers 2 Heat capacity can easily be understood using the example of the beach and the sea. Early in the morning the sand is relatively cool and in the afternoon the sand may become very hot – but the sea remained at the same temperature although both were exposed to the same sunlight. The answer lies in the heat capacities of water versus sand. Much more energy is needed to heat up water than sand. The heat capacity of water is very important and is the amount of heat it requires to raise the temperature of 1mℓ of water with 1 degree Celsius: cw = 4,186 Joules/gK. Heat always flows from a warmer body to the cooler body and this is called heat flow. The heat transfer, Q is the measured solar energy absorbed in terms of the increase in temperature of the water: Qgain = Qloss, where Qloss is the sun energy absorbed and Qgain is temperature rise of the water. The heat gained can be calculated by using the simple heat flow equation: Q = mc∆T, where Q is the heat flow and is measured in joules, m is the mass of the water, c is the heat capacity of the water and ∆T is change of the water temperature. One Joule is equivalent to one Watt of power radiated or dissipated per one second, so 1W = 1J/s. There are many practical examples in nature, and one is one second of sunlight shining on a 10 cm 2 piece of earth surface. Images 1-4: Geysers undergoing testing. "A self-sampled system may not be used for certification purposes because there is no traceability back to a batch that was manufactured. " 3 November 2019 Volume 25 I Number 9 www.plumbingafrica.co.za