Physics Class 11 Chapter 5. Laws of Motion | Page 27

Solution. R = 300m ϴ = 15 o μs = 0.2 o vo = √ Rg tanϴ = √300 * 9.8 * tan 15 o = 28.1 m / s

o vmax = √ Rg( tanϴ + μs) /( 1- μs tanϴ) = √ 300 * 9.8 *( 0.2 + tan 15 o)/( 1-0.2tan15 o) = 38.1 m / s