Maths Class 11 Chapter 3. Trignometric functions | Page 17

Solution: Given, sin x = ½ We know that Sin 30 o = ½ Thus x = 30 o = π / 6

Using theorem, For any real numbers x and y, sin x = sin y implies x = nπ +(– 1) n y, where n ∈ Z

Generic solution is x = nπ +(– 1) n π / 6, where n ∈ Z