Maths Class 11 Chapter 3. Trignometric functions | Page 17

Solution : Given , sin x = ½ We know that Sin 30 o = ½ Thus x = 30 o = π / 6

Using theorem , For any real numbers x and y , sin x = sin y implies x = nπ + (– 1 ) n y , where n ∈ Z

Generic solution is x = nπ + (– 1 ) n π / 6 , where n ∈ Z