PROFIS ENGINEERING
CASE 3 applies for row 1 and row 2: calculate V cbg from row 1 using c a1, row 1.
V b = 7 l e d a
0.2 d a λ a f ′ c c a1
1.5
Reference orange shaded area.
ACI 318-19 Eq.( 17.7.2.2.1a)
l e = MIN h e f | 8d a
= 6.0 in h ef = 10.0 in d a = 0.75 in
normal weight concrete: λ = 1.0 → λ a = 1.0 ACI 318-19 Table 17.2.4.1
V b = [( 7)( 6.0 in / 0.75 in) 0. 2( 0.75 in) 0. 5 ]( 1.0)( 5000 psi) 0. 5( 6.0 in) 1. 5
= 9549 lb V b = 9 λ a f ′ c c a1
1.5 f’ c = 5000 psi
ACI 318-19 Eq.( 17.7.2.2.1b)
c a1, row 1 = 6.0 in
8d a = 6.0 in CONTROLS
V cbg =
V b =( 9)( 1.0)( 5000 psi) 0. 5( 6.0 in) 1. 5 = 9353 lb check: design V b = MIN { 9549 lb; 9353 lb }
A Vc A Vc0
= 9353 lb
ψ ec, V ψ ed, V ψ c, V ψ h, V ψ parallel, V V b
V cbg, row 1 =( 405 in 2 / 162 in 2)( 1.0)( 1.0)( 1.2)( 1.0)( 1.0)( 9353 lb)
= 28,059 lb
f’ c = 5000 psi |
c a1, row 1 = 6.0 in |
ACI 318-19 17.7.2.2 |
A Vc = 405 in 2 |
A Vc0 = 162 in 2 |
ψ ec, V = 1.0 |
ψ ed, V = 1.0 |
ψ c, V = 1.2 |
ψ h, V = 1.0 |
ψ parallel, V = 1.0 |
V b = 9353 lb |
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