PROFIS ENGINEERING
• The spacing( s x12) between col 1 and col 2 is less than c a1, col 1
• A complete failure surface can develop from col 1.
• The failure surface for col 2 will merge with the failure surface for col 1.
• The spacing( s x23) between col 2 and col 3 is greater than c a1, col 1
• A complete failure surface can develop from col 3.
• The spacing( s x34) between col 3 and col 4 is less than c a1, col 1
• The failure surface for col 4 will merge with the failure surface for col 3.
• Case 1 / Case 2 applies for col 1 and col 3.
• V ua, y( acts parallel to x- edge) is assumed to be distributed proportionately between col 1 and col 3 such that 0.5V ua, y acts on col 1 and 1.0V ua, y acts on col 3.
• where ψ parallel, V = 2.0
• A Vc, col 1 =( 1.5c a1, col 1 + s y34 + s y23 + s y12 + c a2, y)( 1.5c a1, col 1)
• Check V ua, y, col 1 / ϕ( V cbg, col 1) ≤ 1.0 where V ua, y, col 1 = 0.5V ua, y
• V cbg, col 3 = A vc, col 3 A vc0 ψ ec, V ψ ed, V ψ c, V ψ h, V ψ parallel, V V b where ψ parallel, V = 2.0
• A Vc, col 3 =( 1.5c a1, col 3 + s y34 + s y23 + s y12 + c a2, y)( h concrete)
• Check V ua, y, col 3 / ϕ( V cbg, col 3) ≤ 1.0 where V ua, y, col 3 = 1.0V ua, y
The shear concrete breakout provisions are satisfied if the Case 1 / Case 2 assumptions are satisfied. Reference page 26 for information on shear load parameters.
• col 1 utilization: if 0.5V ua, y / ϕ( V cbg, col 1) ≤ 1.0 OK
• col 3 utilization: if 1.0V ua, y / ϕ( V cbg, col 3) ≤ 1.0 OK
• MAX {( col 1 utilization);( col 3 utilization)} controls for concrete breakout in shear
NOTES:
2 2
• PROFIS Engineering calculations would assume the resultant shear load V ua = V ua, x + V ua, y acts on the anchors in col 1 and col 3 in lieu of V ua, y such that
• Case 1 / Case 2 for col 1 and col 3
• MAX {( 0.5V ua / ϕV cbg, col 1);( 1.0V ua / ϕV cbg, col 3)} controls for concrete breakout in shear
• This is a conservative assumption. Reference( for example) ACI 318-19 Section 17.7.2.1( d) and the commentary R17.7.2.1:“ For anchors near a corner required to resist a shear force with components normal to each edge, a satisfactory solution is to check the connection independently for each component of the shear force”
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