Curso de Preparación para el Examen de CCNA 200-120 | Page 45

Split the boxes in half again and you get sixteen subnets with sixteen addresses, 0 128 32 15 16 47 48 /28 255.255.255.240 16 Hosts 16 Subnets The next split gives you thirty two subnets with eight addresses, 79 8 0 7 15 23 64 The last split gives sixty four subnets with four addresses each, You can use these squares in any combination to fit your addressing needs. 79 87 0 8 7 16 19 64 68 96 79 83 84 183 224 191 232 215 223 136 247 160 255 168 135 143 167 175 144 152 176 184 147 155 179 187 148 156 180 188 63 151 192 159 200 183 224 191 232 107 195 203 227 235 108 196 204 228 236 103 111 199 207 321 239 112 120 208 216 240 248 91 92 87 159 200 59 104 99 100 88 151 131 139 163 171 132 140 164 172 60 55 75 71 80 168 135 143 167 175 144 152 176 184 128 56 51 31 76 160 47 39 52 72 136 255 43 44 48 27 67 40 36 28 223 192 127 35 15 23 /30 255.255.255.252 4 Hosts 64 Subnets 32 24 20 119 11 12 63 104 239 240 103 111 199 207 321 239 112 120 208 216 240 248 95 3 4 55 96 88 47 56 31 71 207 128 39 48 72 80 40 191 224 208 127 32 24 159 111 95 175 176 192 112 16 /29 255.255.255.248 8 Hosts 32 Subnets 63 96 80 143 144 31 64 160 115 123 211 219 243 251 116 124 212 220 244 252 95 119 127 215 223 247 255 3