Curso de Preparación para el Examen de CCNA 200-120 | Page 45
Split the boxes in half again and you
get sixteen subnets with sixteen
addresses,
0
128
32
15
16
47
48
/28
255.255.255.240
16 Hosts
16 Subnets
The next split gives you thirty two
subnets with eight addresses,
79
8
0
7
15
23
64
The last split gives sixty four subnets
with four addresses each,
You can use these squares in any
combination to fit your addressing
needs.
79
87
0
8
7
16
19
64
68
96
79
83
84
183
224
191
232
215
223
136
247
160
255
168
135
143
167 175
144 152
176
184
147
155
179 187
148 156
180
188
63
151
192
159
200
183
224
191
232
107
195
203
227 235
108
196 204
228
236
103
111
199
207
321 239
112
120
208 216
240
248
91
92
87
159
200
59
104
99
100
88
151
131
139
163 171
132 140
164
172
60
55
75
71
80
168
135
143
167 175
144 152
176
184
128
56
51
31
76
160
47
39
52
72
136
255
43
44
48
27
67
40
36
28
223
192
127
35
15
23
/30
255.255.255.252
4 Hosts
64 Subnets
32
24
20
119
11
12
63
104
239
240
103
111
199
207
321 239
112
120
208 216
240
248
95
3
4
55
96
88
47
56
31
71
207
128
39
48
72
80
40
191
224
208
127
32
24
159
111
95
175
176
192
112
16
/29
255.255.255.248
8 Hosts
32 Subnets
63
96
80
143
144
31
64
160
115
123
211
219
243 251
116
124
212 220
244
252
95
119
127
215
223
247 255
3