Civil Insight: A Technical Magazine Volume 2 | Page 21
CIVIL INSIGHT 2018
TEACHERS’ SECTION
21
Calculation of the free-fi eld deformation ( free-fi eld)
As per the collected earthquake data
The peak ground acceleration at the depth of tunnel (a s ) = (0.9 * a max ) = 0.9 * 0.49 = 0.44 g.
0.9 is the ratios of ground motion at depth to motion at ground surface obtained from Table 1 (Y M AHashash
et al., 2001).
For stiff soil medium, (Source to site distance = 59.9 km) peak ground velocity at the depth of tunnel can be
calculated as,
Peak ground velocity at the depth of tunnel = V s = (k ×a s )
From table 2, (Y M A Hashash et al., 2001), k = ratio of peak ground displacement (cm) to peak ground
acceleration (g), (corresponding to source to site distance) = 135.7 (cm/sec)/g
V s = 135.7* 0.44 = 59.708 cm /sec = 0.597 m/sec
ೞ
Maximum free-fi eld shear strain at the elevation of tunnel = ɀ ୫ୟ୶ =
ೞ
C s = Apparent velocity of s-wave propagation in soil
C s (for rock) 750 m/sec
For stiff soil = 200-750 m/sec
For soft soil < 200 m/sec.
ɀ ୫ୟ୶ = 0.597 / 750 = 0.000796.
Free-fi eld deformation = free-fi eld= ɀ ୫ୟ୶ *H
= 0.000796 * 6.8 = 0.0054128m = 5.4128 mm
Calculation of Flexibility ratio (FR) [J H Wood, 2007]
Figure 3: Unit force applied at the roof level
In assessing soil-structure interaction effects on underground structures it is usual to defi ne fl exibility ratio.
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ୋ ౣ ൈ
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In these expressions, the unit racking stiffness is simply the reciprocal of the lateral racking defl ection,
ଵ
ܵ ଵ ൌ , caused by unit concentrated force
ο
For a rectangular frame with arbitrary confi guration, the fl exibility ratio can be determined by
୫ ൌ ሺɏ
ሺ ୫ ሻ ଶ ൈ ሺ ୫ ሻ ଶ = (2000 / 1000) * (75 50) 2 = 11250000 K pa
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ଵଶହൈଶଶǤଵ
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ൌ7.567