Problem #3:
The variable A starts with the value 1.
The variable B starts with the value 10.
The variable C starts with the value 100.
The variable X starts with the value 0.
Store the value of C times 3 in X.
Add the value of B times 6 to the value already in X.
Add the value of A times 5 to the value already in
Display the value in X on the screen.
Output #3:
Pseudocode #3: