Burdge/Overby, Chemistry: Atoms First, 2e Ch14 | Page 30

Q uest i o n s a n d P ro b lem s 14.22 Using data from Appendix 2, calculate ?S° and rxn ?Ssurr for each of the reactions in Problem 14.10 and determine if each reaction is spontaneous at 25°C. 14.23 Using data from Appendix 2, calculate ?S° and rxn ?Ssurr for each of the reactions in Problem 14.11 and determine if each reaction is spontaneous at 25°C. 14.24 When a folded protein in solution is heated to a high enough temperature, its polypeptide chain will unfold to become the denatured protein—a process known as “denaturation.” The temperature at which most of the protein unfolds is called the “melting” temperature. The melting temperature of a certain protein is found to be 63°C, and the enthalpy of denaturation is 510 kJ/mol. Estimate the entropy of denaturation, assuming that the denaturation is a single-step equilibrium process; that is, folded protein denatured protein. The single polypeptide protein chain has 98 amino acids. Calculate the entropy of denaturation per amino acid. Section 14.5:? Predicting Spontaneity Review Questions 14.25 Define free energy. What are its units? 14.26 Why is it more convenient to predict the direction of a reaction in terms of ?Gsys instead of ?Suniv? Under what conditions can ?Gsys be used to predict the spontaneity of a reaction? 14.27 What is the significance of the sign of ?Gsys? 14.28 From the following combinations of ?H and ?S, predict if a process will be spontaneous at a high or low temperature: (a) both ?H and ?S are negative, (b) ?H is negative and ?S is positive, (c) both ?H and ?S are positive, (d) ?H is positive and ?S is negative. Problems 14.29 Assuming that ?H and ?S do not change with temperature, determine ?G for the denaturation in Problem 14.24 at 20°C. 14.30 Calculate ?G° for the following reactions at 25°C: (a) N2(g) + O2(g) 2NO(g) (b) H2O(l) H2O(g) (c) 2C2H2(g) + 5O2(g) 4CO2(g) + 2H2O(l) (Hint: Look up the standard free energies of formation of the reactants and products in Appendix 2.) 14.31 Calculate ?G° for the following reactions at 25°C: (a) 2Mg(s) + O2(g) 2MgO(s) (b) 2SO2(g) + O2(g) 2SO3(g) (c) 2C2H6(g) + 7O2(g) 4CO2(g) + 6H2O(l) (See Appendix 2 for thermodynamic data.) 14.32 From the values of ?H and ?S, predict which of the following reactions would be spontaneous at 25°C: reaction A: ?H = 10.5?kJ/mol, ?S = 30 J/K ? mol; reaction B: ?H = 1.8?kJ/mol, ?S = –113 J/K ? mol. If either of the reactions is nonspontaneous at 25°C, at what temperature might it become spontaneous? 14.33 Find the temperatures at which reactions with the following ?H and ?S values would become spontaneous: (a) ?H = –126?kJ/mol, ?S = 84 J/K ? mol; (b) ?H = –11.7 kJ/mol, ?S = –105?J/K ? mol. bur11184_ch14_570-603.indd 599 599 14.34 The molar heats of fusion and vaporization of ethanol are 7.61 and 26.0 kJ/mol, respectively. Calculate the molar entropy changes for the solid-liquid and liquidvapor transitions for ethanol. At 1 atm pressure, ethanol melts at –117.3°C and boils at 78.3°C. 14.35 The molar heats of fusion and vaporization of mercury are 23.4 and 59.0 kJ/mol, respectively. Calculate the molar entropy changes for the solid-liquid and liquidvapor transitions for mercury. At 1 atm pressure, mercury melts at –38.9°C and boils at 357°C. 14.36 Use the values listed in Appendix 2 to calculate ?G° for the following alcohol fermentation: C6H12O6(s) 2C2H5OH(l) + 2CO2(g) 14.37 Certain bacteria in the soil obtain the necessary energy for growth by oxidizing nitrites to nitrates: 2NO – + O2 2 2NO– 3 Given that the standard Gibbs free energies of formation of NO – and NO – are –34.6 and –110.5 kJ/mol, 2 3 respectively, calculate the amount of Gibbs free energy released when 1 mole of NO – is oxidized to 1 mole 2 of NO –. 3 Section 14.6:?Thermodynamics in Living Systems Review Questions 14.38 What is a coupled reaction? What is its importance in biological reactions? 14.39 What is th R&??R?bE??&????v?6?&V7F???3??6??WFF????&?&?V??B?C?&VfW'&??rF?F?R?WF&??2&?6W72??f??f??rv?V6?6R???f?wW&RB?r?6?7V?FRF?R????V??V?&W"?b???W0??bEF?B6?&R7??F?W6??VBg&??Eg&??F?P?'&V?F?v??b???R?bv?V6?6R?FF?F????&?&?V?0??B?C?&VF?7BF?R6?v?2?b(?d??(?e2??B(?dr?bF?R7?7FV?f?"F?Rf????v??r&?6W76W2BF??????????V?G2B( 3c +2??"?( ???????V?G2B( 3sr?|+2??2????????V?G2B( 3 +2??F?R??&???V?F??r???@??b??????2( 3sr?|+2??B?C ?7GVFV?B?6VBr?bV6??bF?&VR6???V?G2??"??B2??6??F??W"?Bf?V?BF?BgFW"vVV????6??vR?B?67W'&VB??ffW"6??R?76?&?RW???F???0?f?"F?Rf7BF?B??&V7F???2F????6R?77V?RF?B??"??B2&RF?F???66?&?R?V?G2?B?C0?F?RV?F???6??vR??F?RFV?GW&F????b6W'F???&?FV???2#R????????bF?RV?G&??6??vR?0?3?r???(??????6?7V?FRF?R????V?FV?W&GW&R@?v??6?F?R&?FV??v?V?BFV?GW&R7??F?V?W6??B?C@?6??6?FW"F?Rf????v??rf7G3?vFW"g&VW?W0?7??F?V?W6?B( 3\+2?BF???B?6R?2??vW ?V?G&??F???V?BvFW"?W??????r7??F?V?W0?&?6W726??VBF?FV7&V6R??V?G&???B?CP??????V???G&FR???D??2?F?76??fW27??F?V?W6???BV?F?F?W&?6????vFW"?v?B6???RFVGV6P?&?WBF?R6?v??b(?e2f?"F?R6??WF???&?6W73??????2#???