NOVEMBER CHALLENGE " The Distribution Dilemma "
Mark ' s warehouse has ten pallets of brand-new laptops , each destined for shipment to a different country . All of the laptops weigh 2 kg and are identical , except for the pallet destined to go to the U . S ., which have two additional USB C ports . The trucks are waiting . Mark doesn ' t have much time . What ' s the fastest way for him to make sure the right pallets go to the right countries if the only tool he has is a digital balance ?
Please send you answers to Thomas Selling via e-mail :
thomasselling @ me . com Correct responses will be recognized in the future issues of the New Hampshire Civil Engineer .
OCTOBER SOLUTION
In one day , the first faucet will output a volume of water equal to 12V .
The second faucet / tap will output 13V , the third will output 14V , and the fourth will output 4 times the capacity of the pool ( all in one day ), as hours would be a quarter of a day . Adding these volumes up , we have that all four faucets will output 11261 / 12 times the capacity of the pool in one day .
Therefore , the time taken to output a volume of water equal to the volume of the pool will be
245.08333 = 4.72 hours , if we rearrange 61 / 12 6112V = 24for V .
We have assumed that the faucets run at the same time , and that their flow rates are constant .
Correct Responses Submitted By : Michael J . Dugas , P . E ., NHDOT Bruce A . Thomas , P . E ., Town Engineer , Hooksett , NH Chad F . Poland , EIT , Mitchie Corp . Donald A . Provencher , P . E ., Provencher Engineering , LLC