Your Practice Set – Applications and Interpretation for IBDP Mathematics
Solution
( a ) ( i ) 4 A1
( ii ) 3 A1
( b ) |
The period of
V
2
|
|
2�
�
4
|
( M1 ) for valid approach |
|
� � s
2
|
A1 |
( c ) V1� V2 � 4cos ( 4t � 0.1 ) � 3cos 4t
( d ) ( i )
V �V � e � e ( M1 ) for valid approach
( 4t�0.1 ) i 4ti
1 2
Re ( 4 ) Re ( 3 ) V �V � e � e
( A1 ) for correct approach
( 4t�0.1 ) i 4ti
1 2
Re ( 4 3 ) V �V � e e �
4ti 0.1i
1 2
Re ( ( 4 3 )) �z � w � e � A1
0.1i 4 3
0.1i z� 4e z � 4 ( cos 0.1� isin 0.1 )
A1
( ii ) w � 3 w � 3 ( cos 0� isin 0 )
A1
( e ) ( i ) z� w� 4 ( cos 0.1� isin 0.1 ) �3 ( cos 0� isin 0 ) z� w� ( 4cos 0.1�
3cos 0 )
�i ( 4sin 0.1�
3sin 0 )
( M1 ) for valid approach
z� w� 6.980016661 � 0.3993336666i ( A1 ) for correct values
2 2
L � 6.980016661 � 0.3993336666 M1 L � 6.991430466 L � 6.99
A1
[ 2 ]
[ 2 ]
[ 3 ]
[ 2 ]
( ii )
0.3993336666
� � arctan M1 6 . 980016661
� � 0.0571486937
� � 0.0571 A1
[ 6 ]
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