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Paper 1 – Equations of Tangents and Normals
Example
�
Let f( x) � 2e x .
( a ) Find f� ( x) .
( b ) ( i ) Find the gradient of the tangent to the curve of f at ( 0 , 2 ) .
[ 2 ]
( ii ) Hence , find the equation of the tangent to the curve of f at ( 0 , 2 ) , giving the answer in the form y �ax � b .
[ 5 ]
Solution
�x
( a ) f�( x) �2 ( e )( � 1 ) ( M1 ) for chain rule
� f�( x) �� 2e x A1
( b ) |
( i ) |
The gradient of the tangent |
|
|
� f � ( 0 ) |
|
��
2e �0
|
( M1 ) for substitution |
|
��
2
|
A1 |
( ii ) The equation of the tangent : y � �2x � b ( M1 ) for setting equation
2 � �2 ( 0 ) � b
( M1 ) for substitution b � 2 � y� �2x� 2 A1
[ 2 ]
[ 5 ]
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