Analysis and Approaches for IBDP Maths Ebook 1 | Page 49

Front Page
Solution
(a) f( x) � 0
(M1) for equation equals to 0
5 3x
�e x
2
� 0
x � 1.29
A1 N2
(b) The minimum point is (2.63, � 1.14) . A2 N2
(c) For correct domain and endpoints at x � 0 and
x � 8
A1
For correct maximum point
A1
For correct concavity A1 N3
[2]
[2]
[3]
4
www.seprodstore.com
41