Mass by volume percentage
CH4 + 2O2-- > CO2 + 2H2O
V1 volume of CO = ½ V1 volume of O2 = V1 volume of CO2
V2 volume of CH4 = 2V2 volume O2 = V2 volume of CO2 V1 / 2 + 2V2 = 13.0 cm 3
Treating of residual gases with KOH solution would cause the absorption of CO2
V1 + V2 = 14.0 cm 3
V1 = 10 cm 3
V2 = 4.0 cm 3
V3 = 6.0 cm 3
Volume % of CO = 10 / 20 x 100 = 50 Volume % of CH4 = 4 / 20 X 100 = 20 Volume % of He = 100-( 50 + 20) = 30
Mass by volume percentage
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Mass by volume percentage can be defined as the mass of solute dissolved in 100 mL of the solution.
For instance, mass by volume percent of a solution with 1 g of solute dissolved in 100 mL of solution will be 1 % or 1 %( mass / volume).
o Mathematically, Mass by volume % =
Problem:
Rashida dissolved 40g of sugar in 600 mL of sugar solution. Calculate the mass by volume percentage.
Solution: Mass by volume % =